Question
Factorise:
$2(x+y)^2-9(x+y)-5$

Answer

Let $x+y=z$
Then, $2(x+y)^2-9(x+y)-5$
$=2 z^2-9 z-5$
$=2 z^2-10 z+z-5$
$=2 z(z-5)+1(z-5)$
$=(z-5)(2 z+1)$
Now, replacing $z$ by $(x+y)$, we get
$2(x+y)^2-9(x+y)-5$
$=[(x+y)-5][(2(x+y)+1)]$
$=(x+y-5)(2 x+2 y+1)$

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