Question
Factorise: $3+23 z-8 z^2$
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Answer
$3+23 z-8 z^2$
$=3+24 z-z-8 z^2$
$\{3 × (-8) = -24, -24 = 24 × (-1), 23 = 24 - 1\}$
$= 3(1 + 8z) - z(1 + 8z)$
$ = (1 + 8z)(3 - z)$
$=3+24 z-z-8 z^2$
$\{3 × (-8) = -24, -24 = 24 × (-1), 23 = 24 - 1\}$
$= 3(1 + 8z) - z(1 + 8z)$
$ = (1 + 8z)(3 - z)$
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