Question
Factorise:
$3+23 z-8 z^2$

Answer

$3+23 z-8 z^2$
$=3+24 z-z-8 z^2$
$\{3 \times(-8)=-24,-24=24 \times(-1), 23=24-1\}$
$=3(1+8 z)-z(1+8 z)$
$=(1+8 z)(3-z)$

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