MCQ
Factorise $(3 − 4y − 7y^2)^2− (4y + 1)^2$
- A$(7y^2− 4) (7y^2− 8y − 2)$
- ✓$(4 − 7y^2) (2 − 8y − 7y^2)$
- C$(7y^2− 4) (2 − 8y − 7y^2)$
- D$(4 − 7y^2) (7y^2+ 8y − 2)$
✓
Answer
Correct option: B.
$(4 − 7y^2) (2 − 8y − 7y^2)$
We have, $(3 − 4y − 7y^2) 2 − (4y + 1)^2$
We know that $a^2− b^2= (a + b) (a − b)$
$\therefore \Rightarrow (3 − 4y − 7y^2+ 4y + 1) (3 − 4y − 7y^2− 4y − 1)$
$\Rightarrow (4 − 7y^2) (2 − 8y − 7y^2)$
Hence, this is the answer.
We know that $a^2− b^2= (a + b) (a − b)$
$\therefore \Rightarrow (3 − 4y − 7y^2+ 4y + 1) (3 − 4y − 7y^2− 4y − 1)$
$\Rightarrow (4 − 7y^2) (2 − 8y − 7y^2)$
Hence, this is the answer.
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