Question
Factorise $: 3 - a (4 + 7a)$
✓
Answer
$3 - a (4 + 7a)$
$= 3 - 4a - 7a^2$
$= 3 - 7a + 3a - 7a^2$
$= 1( 3 - 7a ) + a( 3 - 7a )$
$= ( 3 - 7a )( a + 1 )$
$= 3 - 4a - 7a^2$
$= 3 - 7a + 3a - 7a^2$
$= 1( 3 - 7a ) + a( 3 - 7a )$
$= ( 3 - 7a )( a + 1 )$
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