Question
Factorise:
$(3 a-1)^2-6 a+2$
$(3 a-1)^2-6 a+2$
✓
Answer
$(3 a-1)^2-6 a+2$
$=(3 a-1)^2-2(3 a-1)$
$=(3 a-1)[(3 a-1)-2]$
$=(3 a-1)(3 a-3)$
$=3(3 a-1)(a-1)$
$=(3 a-1)^2-2(3 a-1)$
$=(3 a-1)[(3 a-1)-2]$
$=(3 a-1)(3 a-3)$
$=3(3 a-1)(a-1)$
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