Question
Factorise: $3 z^2-10 z+8$

Answer

$3 z^2-10 z+8$
$=3 z^2-6 z-4 z+8$
$\{24 = 3 × 8, 24 = (-6) × (-4), -10 = -6 - 4\}$
$= 3z(z - 2) - 4(z - 2) $
$= (z - 2)(3z - 4)$

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