Question
Factorise $: 4(a + b) - 6(a + b)^2$
✓
Answer
$4(a + b) - 6(a + b)^2$
$= (a + b)[4 - 6(a + b)]$
$= 2(a + b)(2 - 3a - 3b)$
$= 2(a + b)(2 - 3a - 3b)$
$= (a + b)[4 - 6(a + b)]$
$= 2(a + b)(2 - 3a - 3b)$
$= 2(a + b)(2 - 3a - 3b)$
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