Question
Factorise $: 4a^2- (4b^2+ 4bc + c^2)$
✓
Answer
$4a^2- (4b^2+ 4bc + c^2)$
$= ( 2a )^2 - ( 2b + c )^2$
$= [ 2a - ( 2b + c )][ 2a + (2b + c )] [\because a^2 - b^2 = ( a + b )( a - b )]$
$= [ 2a - 2b - c ][ 2a + 2b + c ]$
$= ( 2a )^2 - ( 2b + c )^2$
$= [ 2a - ( 2b + c )][ 2a + (2b + c )] [\because a^2 - b^2 = ( a + b )( a - b )]$
$= [ 2a - 2b - c ][ 2a + 2b + c ]$
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