Question
Factorise:
$4a^2 - 9b^2 - 2a - 3b$
$4a^2 - 9b^2 - 2a - 3b$
✓
Answer
$4a^2 - 9b^2 - 2a - 3b$
$= (2a)^2 - (3b)^2 - (2a + 3b)$
$= (2a - 3b)(2a + 3b) - (2a + 3b)$
$= (2a + 3b)(2a - 3b - 1)$
$= (2a)^2 - (3b)^2 - (2a + 3b)$
$= (2a - 3b)(2a + 3b) - (2a + 3b)$
$= (2a + 3b)(2a - 3b - 1)$
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