Question
Factorise$ : 4a^2b - 9b^3$

Answer

$4a^2b - 9b^3$
$= b( 4a^2 - 9b^2 )$
$= b[ (2a)^2 - (3b)^2 ]$
$= b( 2a - 3b )( 2a + 3b ) [ \because a2 - b2 = ( a + b )( a - b )]$

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