Question
Factorise: $4 n^2-8 n+3$
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Answer
$4 n^2-8 n+3$
$=4 n^2-6 n-2 n+3$
${4 × 3 = 12, 12 = (-6) × (-2), - 8 = -6 - 2}$
$= 2n(2n - 3) - 1(2n - 3)$
$ = (2n - 3)(2n - 1)$
$=4 n^2-6 n-2 n+3$
${4 × 3 = 12, 12 = (-6) × (-2), - 8 = -6 - 2}$
$= 2n(2n - 3) - 1(2n - 3)$
$ = (2n - 3)(2n - 1)$
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