Factorise: 4 n^2-8 n+3 - Vidyadip

Question

Factorise:
$4 n^2-8 n+3$

✓

Answer

$4 n^2-8 n+3$
$=4 n^2-6 n-2 n+3$
$\{4 \times 3=12,12=(-6) \times(-2),-8=-6-2\}$
$=2 n(2 n-3)-1(2 n-3)$
$=(2 n-3)(2 n-1)$

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