Question
Factorise:
$ 4 y^2+20 y+25 $

Answer

$ 4 y^2+20 y+25 $
$=(2 y)^2+2 \times 2 y \times 5+(5)^2 $
$=\left(2 y^2+5\right)^2 $
$\left\{\therefore a^2+2 a b+b=(a+b)^2\right\} $

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