Question
Factorise: $63a^2– 112b^2$
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Answer
$63a^2– 112b^2$
$= 7(9a^2– 16b^2)$
$= 7 {(3a)^2– (4b)^2}$
$= 7 (3a – 4b) (3a + 4b). . . . [$Applying Identity $III]$
$= 7(9a^2– 16b^2)$
$= 7 {(3a)^2– (4b)^2}$
$= 7 (3a – 4b) (3a + 4b). . . . [$Applying Identity $III]$
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