Question
Factorise: $63 a^2-112 b^2=7$

Answer

Using: $a^2-b^2=(a+b)(a-b) $
$63 a^2-112 b^2=7$
$\left(9 a^2-16 b^2\right)$
$=7 [(3 a)^2-(4 b)^2]$
$=7(3 a+4 b)(3 a-4 b).$

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