Question
Factorise:
$63 a^2 b^2-7$

Answer

$63 a^2 b^2-7$
$=7\left(9 a^2 b^2-1\right)$
$=7(3 a b)^2-(1)^2$
$=7(3 a b+1)(3 a b-1)$

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