Question
Factorise:
$64 a^3-343$
$64 a^3-343$
✓
Answer
$64 a^3-343$
$=(4 a)^3-(7)^3$
$=(4 a-7)\left[(4 a)^2+(4 a)(7)+(7)^2\right]$
$=(4 a-7)\left(16 a^2+28 a+49\right)$
$=64+112+196 a-112-196 a-343$
$=64 a^3-343$
$=(4 a)^3-(7)^3$
$=(4 a-7)\left[(4 a)^2+(4 a)(7)+(7)^2\right]$
$=(4 a-7)\left(16 a^2+28 a+49\right)$
$=64+112+196 a-112-196 a-343$
$=64 a^3-343$
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