Question
Factorise :$64 m^3-343 n^3$

Answer

$64 m^3-343 n^3$
$=(4 m)^3-(7 n)^3=(4 m-7 n)\left\{(4 m)^2+(4 m)(7 n)+(7 n)^2\right\}$
$=(4 m-7 n)\left(16 m^2+28 m n+49 n^2\right)$

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