Factorise: 6 p^2+11 p-10 - Vidyadip

Question

Factorise: $6 p^2+11 p-10$

✓

Answer

$6 p^2+11 p-10$
$=6 x^2+15 x-4 x-10$
${6 × (-10) = 60, -60 = 15 × (-4), 11 = 15 - 4}$
$= 3x(2x + 5) - 2(2x + 5) $
$= (3x - 2)(2x + 5)$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "2 Marks Questions" from Factorisation→Factorisation — all question types→MATHS STD 8 question papers→Gujarat Board STD 8 question papers→Gujarat Board question paper generator→

Similar questions

The sum of two rational numbers is $−2.$ If one of the numbers is $\frac{-14}{5}$, find the other.

Replace $A, B, C$ by suitable numerals. $\underline{ \ \ \ \ 4 \ \text{C B } \ 6\\+3 \ \ 6\ \ 9\text{ A}}\\ \ \ \ \ 8\ \ 1\ \ 7\ \ 3$

Find the squares of the following numbers: $127$

Which of the two rational numbers is greater in the given pair? $\frac{-3}{4}\text{ or }\frac{1}{4}$

Factorise: $(x + y)(2x + 5) - (x + y)(x + 3)$

Express: $56\%$ as a ratio.

Factorise:
$9a(3a - 5b) - 12a^2(3a - 5b)$

Factorize of the following algebraic expressions:
$9a(6a - 5b) - 12a^2(6a - 5b)$

Take four set-squares from your and your friend's Instrument boxes. Use different numbers of them to place side-by-side and obtain different trapeziums.
If the non-parallel sides of a trapezium are of equal length, we call it an Isosceles trapezium. Did you get an isosceles trapezium in any of your Investigations given above?

Evaluate:$\sqrt{10.0489}$