Question
Factorise:
7a3 + 56b3

Answer

7a3 + 56b3
= 7(a3 + 8b3)
= 7[(a)3 + (2b)3]
= 7(a + 2b)[a2 - a × 2b + (2b)2] Since a3 + b3 = (a + b)(a2 - a × b + b2)
= 7(a + 2b)(a2 - 2ab + 4b2)

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