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Factorisation — Maths STD 8 — Question

Maharashtra BoardEnglish MediumSTD 8MathsFactorisation2 Marks
Question
Factorise:
$7 y^2-19 y-6$
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Answer

$7 y^2-19 y-6$
$=7 y^2-21 y+2 y-6$
$\{7 \times(-6)=-42,-42=-21 \times 2,-19=-21+3\}$
$=7 y(y-3)+2(y-3)$
$=(y-3)(7 y+2)$

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