Question
Factorise:
$8 - 27b^3 - 343c^3 - 126bc$

Answer

$8 - 27b^3 - 343c^3 - 126bc$
$= (2)^3 + (-3b)^3 + (-7c)^3 - 3 \times (2) \times (-3b) \times (-7c)$
$= [2 + (-3b) + (-7c)[(2)^2 + (-3b)^2 + (-7c)^2 - (2)(-3b) - (-3b)(-7c) - (2)(-7c)]$
$= (2 - 3b - 7c)(4 + 9b^2 + 49c^2 + 6b - 21bc + 14c)$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free