Question
Factorise:
8x2y3 - x5
8x2y3 - x5
✓
Answer
8x2y3 - x5
= x2(8y3 - x3)
= x2[(2y)3 - x3]
= x2[(2y - x)[(2y)2 + (2y)(x) + x2]
= x2(2y - x)(4y2 + 2xy + x2)
= x2(8y3 - x3)
= x2[(2y)3 - x3]
= x2[(2y - x)[(2y)2 + (2y)(x) + x2]
= x2(2y - x)(4y2 + 2xy + x2)
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