Question
Factorise:
$9a^2 + 6a + 1 - 36b^2$

Answer

$9a^2 + 6a + 1 - 36b^2$
$= (9a^2 + 6a + 1) - 36b^2$
$= [(3a)^2 + 2(3a)(1) + (1)^2] - (6b)^2$
$= (3a + 1)^2 - (6b)^2$
$= (3a + 1 - 6b)(3a + 1 + 6b)$

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