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Factorisation — Maths STD 8 — Question

Maharashtra BoardEnglish MediumSTD 8MathsFactorisation2 Marks
Question
Factorise:
$9 a^2-b^2+4 b-4$
✓

Answer

$9 a^2-b^2+4 b-4$
$=9 a^2-\left(b^2-4 b+4\right)$
$=(3 a)^2-\left[(b)^2-2 \times b \times 2+(2)^2\right.$
$=(3 a)^2-(b-2)^2$
$\left\{\because a^2-2 a b+b^2=(a-b)^2\right\}$
$=(3 a+b-2)(3 a-b+2)$
$\left\{\because a^2-b^2=(a+b)(a-b)\right\}$

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