Question
Factorise: $ 9 y^2-12 y+4$
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Answer
$ 9 y^2-12 y+4$
$=(3 y)^2-2 \times 3 y \times 2+(2)^2 $
$\{\because a 2-2 a b+b 2=(a-b) 2\}$
$ =(3 y-2)^2$
$=(3 y)^2-2 \times 3 y \times 2+(2)^2 $
$\{\because a 2-2 a b+b 2=(a-b) 2\}$
$ =(3 y-2)^2$
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