Question
Factorise:
a12 - b12

Answer

a12 - b12
= (a6)2 - (b6)2
= (a6 - b6)(a6 + b6)
= [(a3)2 - (b3)2][(a2)3 + (b2)3]
= (a3 - b3)(a3 + b3)[(a2 + b2)(a4 - a2b2 + b4)]
= (a - b)(a2 + ab + b2)(a + b)(a2 - ab + b2)(a2 + b2)(a4 - a2b2 + b4)
= (a - b)(a + b)(a2 + b2)(a2 + ab + b2)(a2 - ab + b2)(a4 - a2b2 + b4)

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