Question
Factorise$ : a^2- (2a + 3b)^2$

Answer

$a^2- (2a + 3b)^2$
$= a^2 - ( 2a + 3b )^2$
$= ( a - 2a - 3b )( a + 2a + 3b ) [ \because a^2 - b^2 = ( a + b )(a - b)]$
$= ( - a - 3b )( 3a + 3b )$
$= - 3( a + 3b )( a + b )$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free