Question
Factorise $: a^2- 81 (b-c)^2$

Answer

$a^2- 81 (b-c)^2$
$= ( a )^2 - [ 9( b - c ) ]^2$
$= [ a - ( 9b - 9c )][ a + ( 9b - 9c )] [ \because a^2 - b^2 = ( a + b )( a - b )]$
$= ( a - 9b + 9c )( a + 9b - 9c )$

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