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Factorisation — MATHEMATICS STD 9 — Question

ICSE BoardEnglish MediumSTD 9MATHEMATICSFactorisation2 Marks
Question
Factorise$ :a^3- 27$
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Answer

$a^3 - 27$
$= ( a )^3 - ( 3 )^3$
$= ( a - 3 )[ (a)^2 + a x^3 + (3)^2 ] [ \because a^3 - b^3 = ( a - b )( a^2 + ab + b^2 )]$
$= ( a - 3 )[ a^2 + 3a + 9 ]$

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