Download App

Factorisation of Polynomials — MATHS STD 9 — Question

Rajasthan BoardEnglish MediumSTD 9MATHSFactorisation of Polynomials2 Marks
Question
Factorise $: a^3 + 8b^3 + 64c^3 - 24abc$
✓

Answer

$a^3 + 8b^3 + 64c^3 - 24abc$
$= a^3 + (2b)^3 + (4c)^3 - 3 \times a \times 2b \times 4c$
$= (a + 2b + 4c)[a^2 + (2b)^2 + (4c)^2 - a \times 2b - 2b \times 4c - 4c \times a]$
$= (a + 2b + 4c)(a^2 + 4b^2 + 16c^2 - 2ab - 8bc - 4ca)$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "2 Marks Questions" from Factorisation of Polynomials→Factorisation of Polynomials — all question types→MATHS STD 9 question papers→Rajasthan Board STD 9 question papers→Rajasthan Board question paper generator→

Similar questions

Which of the following points lie on the x-asis?
  1. A(0, 8)
  2. B(4, 0)
  3. C(0, -3)
  4. D(-6, 0)
  5. E(2, 1)
  6. F(-2, -1)
  7. G(-1, 0)
  8. H(0, 2)
→
Simplify:
$\big(5+\sqrt{7}\big)\big(2+\sqrt{5}\big)$
→
Factorise:$x^6 - 7x^3 - 8$
→
Expand:$(5a - 3b)^3$​​​​​​​
→
If $a + b + c = 0,$ then write the value of $a^3 + b^3 + c^3.$
→
Simplify:
$\Big(\frac{32}{243}\Big)^{-\frac{4}{5}}$
→
Simplify the following:
$\frac{5\times25^{\text{n}+1}-25\times5^{2\text{n}}}{5\times5^{2\text{n}+3}-(25)^{\text{n}+1}}$
→
The number of children in 10 families of a locality are: 2, 4, 3, 4, 2, 0, 3, 5, 1, 6.
Find the mean number of children per family.
→
Rationalise the denominator of the following:
$\frac{1}{2+\sqrt{3}}$
→
Find three different irrational numbers between the rational numbers  $\frac {5} {9} $ and $\frac {9} {11} $.
→