Question
Factorise:
$a^3+8 b^3+64 c^3-24 a b c$

Answer

$a^3+8 b^3+64 c^3-24 a b c$
$=a^3+(2 b)^3+(4 c)^3-3 \times a \times 2 b \times 4 c$
$=(a+2 b+4 c)\left[a^2+(2 b)^2+(4 c)^2-a \times 2 b-2 b \times 4 c-4 c \times a\right]$
$=(a+2 b+4 c)\left(a^2+4 b^2+16 c^2-2 a b-8 b c-4 c a\right)$

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