Question
Factorise:
$a^3 x^3-3 a^2 b x^2+3 a b^2 x-b^3$
$a^3 x^3-3 a^2 b x^2+3 a b^2 x-b^3$
✓
Answer
$a^3 x^3-3 a^2 b x^2+3 a b^2 x-b^3$
$(a x)^3-(b)^3-3(a x)^2(b)+(a x)(b)^2$
$=(a x-b)^3$
Hence, factorisation of $a^3 x^3-3 a^2 b x^2+3 a b^2 x-b^3$ is $=(a x-b)^3$
$(a x)^3-(b)^3-3(a x)^2(b)+(a x)(b)^2$
$=(a x-b)^3$
Hence, factorisation of $a^3 x^3-3 a^2 b x^2+3 a b^2 x-b^3$ is $=(a x-b)^3$
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