Download App

Factorisation of Polynomials — Maths STD 9 — Question

Gujarat BoardEnglish MediumSTD 9MathsFactorisation of Polynomials2 Marks
Question
Factorise:
(ax + by)2 + (bx - ay)2
✓

Answer

(ax + by)2 + (bx - ay)2
= a2x2 + b2y2 + 2abxy + b2x2 + a2y2 - 2abxy
= a2x2 + b2y2 + b2x2 + a2y2
= a2x2 + b2x2 + b2y2 + a2y2
= x2(a2 + b2) + y2(a2 + b2)
= (a2 + b2)(x2 + y2)

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "2 Marks Questions" from Factorisation of Polynomials→Factorisation of Polynomials — all question types→Maths STD 9 question papers→Gujarat Board STD 9 question papers→Gujarat Board question paper generator→

Similar questions

Simplify:

$\sqrt[5]{(32)^{-3}}$

→
Simplify the following expression:

$(2\sqrt{5}+3\sqrt{2})^2$

→
Simplify the following:
$\Big(\frac{\text{x}^2\text{y}^2}{\text{a}^2\text{b}^2}\Big)^\text{n}$
→
Find the value of x in the following:
$\frac{3^{3\text{x}}\times3^{2\text{x}}}{3^\text{x}}=\sqrt[4]{3^{20}}$
→
Solve the equation 3x + 2 = x - 8, and represent the solution on:
The number line.
→
Find the value of x in the following:
5x - 3 × 32x - 8 = 225
→
Evaluate:
483 - 303 - 183
→
Construct the angles of the following measurements:
75°
→
Find the value of:
x3 + y3 - 12xy + 64, when x + y = -4
→
The sides AB and CD of a parallelogram ABCD are bisected at E and F. prove that EBFD is a parellelogram.
→