Question
Factorise by the grouping method $: 16 (a + b)^2- 4a - 4b$
✓
Answer
$16 (a + b)^2 - 4a - 4b$
$= 16(a+b)^2- 4(a+b)$
$= (a + b) [16 (a + b) - 4]$
$= 4(a+b)[4(a+b)- 1]$
$= 4(a+b) (4a+4b- 1)$
$= 16(a+b)^2- 4(a+b)$
$= (a + b) [16 (a + b) - 4]$
$= 4(a+b)[4(a+b)- 1]$
$= 4(a+b) (4a+4b- 1)$
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