Question
Factorise:$\frac{3}{5}\text{x}^2-\frac{19}{5}\text{x}+4$

Answer

$\frac{3}{5}\text{x}^2-\frac{19}{5}\text{x}+4$$=\frac{3}{5}\text{x}^2+\frac{4}{5}\text{x}-3\text{x}+4$
$=\frac{\text{x}}{5}(3\text{x}-4)-1(3\text{x}-4)$
$=\Big(\frac{\text{x}}{5}-1\Big)(3\text{x}-4)$

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