Question
Factorise:$\frac{\text{x}^3}{216}-8\text{y}^3$

Answer

$\frac{\text{x}^3}{216}-8\text{y}^3$$=\Big(\frac{\text{x}}{6}\Big)^3-(2\text{y})^3$
$=\Big(\frac{\text{x}}{6}-2\text{y}\Big)\bigg[\Big(\frac{\text{x}}{6}\Big)^2+\Big(\frac{\text{x}}{6}\Big)(2\text{y})+(2\text{y})^2\bigg]$
$=\Big(\frac{\text{x}}{6}-2\text{y}\Big)\Big(\frac{\text{x}^2}{36}+\frac{\text{xy}}{3}+4\text{y}^2\Big)$

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