Question
Factorise: $(l+3)^2-(l-m)^2$​​​​​​​

Answer

$(l+3)^2-(l-m)^2$
$= (l + m + l - m)(l + m - l + m)$
$\{\because a2 - b2 = (a + b)(a - b)\}$
$= 2l × 2m = 4lm$

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