Question
Factorise:
$(1+3)^2-(1-m)^2$

Answer

$(1+3)^2-(1-m)^2$
$=(1+m+1-m)(1+m-1+m)$
$\{\because a 2-b 2=(a+b)(a-b)\}$
$= 2l × 2m = 4lm$

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