Factorise: (I+m)^2-41 m - Vidyadip

Question

Factorise:
$(I+m)^2-41 m$

✓

Answer

$(I+m)^2-41 m$
$=I^2+m^2+2 I m-4 I m$
$=I^2+m^2-2 I m$
$=I^2-2 I m+m^2$
$=(I-m)^2$
$\left\{\because a^2+2 a b+b^2=(a+b)^2\right\}$

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