Question
Factorise:
$q^2-10 q+21$

Answer

$q^2-10 q+21$
$=q^2+7 q-3 q+21$
$\{21=(-7) \times(-3),-10=-7-3\}$
$=q(q-7)-3(q-7)$
$=(q-7)(q-3)$

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