Question
Factorise:$\sqrt{2}\text{x}^2+3\text{x}+\sqrt{2}$
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Answer
$\sqrt{2}\text{x}^2+3\text{x}+\sqrt{2}$$=\sqrt{2}\text{x}^2+\text{x}+2\text{x}+\sqrt{2}$
$=\text{x}\big(\sqrt{2}\text{x}+1\big)+\sqrt{2}\big(\sqrt{2}\text{x}+1\big)$
$=\big(\sqrt{2}\text{x}+1\big)\big(\text{x}+\sqrt{2}\big)$
$=\text{x}\big(\sqrt{2}\text{x}+1\big)+\sqrt{2}\big(\sqrt{2}\text{x}+1\big)$
$=\big(\sqrt{2}\text{x}+1\big)\big(\text{x}+\sqrt{2}\big)$
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