Question
Factorise:$\text{x}^2-3\sqrt{5}\text{x}-20$

Answer

$\text{x}^2-3\sqrt{5}\text{x}-20$$=\text{x}^2-4\sqrt{5}\text{x}+\sqrt{5}\text{x}-20$
$=\text{x}(\text{x}-4\sqrt{5})+\sqrt{5}(\text{x}-4\sqrt{5})$
$=\text{x}(\text{x}-4\sqrt{5})(\text{x}+\sqrt{5})$

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