Question
Factorise:$\text{x}^2+3\sqrt{3}\text{x}+6$
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Answer
$\text{x}^2+3\sqrt{3}\text{x}+6$$=\text{x}^2+2\sqrt{3}\text{x}+\sqrt{3}\text{x}+6$
$=\text{x}(\text{x}+2\sqrt{3})+\sqrt{3}(\text{x}+2\sqrt{3})$
$=(\text{x}+2\sqrt{3})(\text{x}+\sqrt{3})$
$=\text{x}(\text{x}+2\sqrt{3})+\sqrt{3}(\text{x}+2\sqrt{3})$
$=(\text{x}+2\sqrt{3})(\text{x}+\sqrt{3})$
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