Question
Factorise:$\text{x}^2+6\sqrt{6}\text{x}+48$

Answer

$\text{x}^2+6\sqrt{6}\text{x}+48$$=\text{x}^2+4\sqrt{6}\text{x}+2\sqrt{6}\text{x}+48$
$=\text{x}(\text{x}+4\sqrt{6})+2\sqrt{6}(\text{x}+4\sqrt{6})$
$=(\text{x}+4\sqrt{6})(\text{x}+2\sqrt{6})$

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