Question
Factorise:$\text{x}^2+\sqrt{2}\text{x}-24$
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Answer
$\text{x}^2+\sqrt{2}\text{x}-24$$=\text{x}^2+4\sqrt{2}\text{x}-3\sqrt{2}\text{x}-24$
$=\text{x}(\text{x}+4\sqrt{2})-3\sqrt{2}(\text{x}+4\sqrt{2})$
$=(\text{x}-4\sqrt{2})(\text{x}-3\sqrt{2})$
$=\text{x}(\text{x}+4\sqrt{2})-3\sqrt{2}(\text{x}+4\sqrt{2})$
$=(\text{x}-4\sqrt{2})(\text{x}-3\sqrt{2})$
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