Question
Factorise the expression and divide them as directed: $39 y^3\left(50 y^2-98\right) \div 26 y^2(5 y+7)$

Answer

$39 y^3\left(50 y^2-98\right) \div 26 y^2(5 y+7)$
$ = \frac{{39{y^3}(50{y^2} - 98)}}{{26{y^2}(5y + 7)}}$
$ = \frac{{39{y^3} \times 2 \times (25{y^2} - 49)}}{{26{y^2}(5y + 7)}}$
$ = \frac{{39{y^3} \times 2 \times \{ {{(5y)}^2} - {{(7)}^2}\} }}{{26{y^2}(5y + 7)}}$
$ = \frac{{39{y^3} \times 2 \times (5y + 7)(5y - 7)}}{{26{y^2}(5y - 7)}}$. . . . [Using Identity III
$= 3y (5y – 7)$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free