Question
Factorise the expression: $(l + m)^2– 4lm$
(Hint: Expand $( l + m)^2$ first)

Answer

$(l + m)^2– 4lm$
$= (l^2+ 2lm + m^2) – 4lm. . . .$ [Using Identity $I]$
$= l^2+ (2lm – 4lm) + m^2 . . .$ [Combining the like terms]
$= l^2– 2lm + m^2$
$= (l)^2– 2(l) (m) + (m)^2$
$= (l – m)^2 . . .$ [Applying Identity $II]$

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