Question
Factorise the expressions and divide them as directed: $(3x^2- 48) ÷ (x - 4)$
✓
Answer
$(3x^2- 48) ÷ (x - 4)$
We have,$=\frac{3\text{x}^2-48}{\text{x}-4}$
$=\frac{3(\text{x}^2-16)}{\text{x}-4}$
$=\frac{3(\text{x}^2-4^2)}{\text{x}-4}$
$=\frac{3(\text{x}+4)(\text{x}-4)}{\text{x}-4} [\therefore\text{a}^2-\text{b}^2=(\text{a}+\text{b})(\text{a}-\text{b})$
$=3(\text{x}+4)$
We have,$=\frac{3\text{x}^2-48}{\text{x}-4}$
$=\frac{3(\text{x}^2-16)}{\text{x}-4}$
$=\frac{3(\text{x}^2-4^2)}{\text{x}-4}$
$=\frac{3(\text{x}+4)(\text{x}-4)}{\text{x}-4} [\therefore\text{a}^2-\text{b}^2=(\text{a}+\text{b})(\text{a}-\text{b})$
$=3(\text{x}+4)$
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